【帮忙】一道数学题,很简单的
RT,俺不会做了,谁来帮俺做下,明早6:00前要答案~~麻烦大家了,最好写点步骤~化简: =2lg2+lg+^1/2
=2lg2+lg+1
PS:
S___
\/ A = A^(1/2) 原帖由 hiddern70 于 2008-10-17 01:09 发表 http://bbs.aptx.cn/images/common/back.gif
=2lg2+lg+^1/2
=2lg2+lg+1
PS:
S___
\/ A = A^(1/2) incorrect...conceptual mistakes =(1/2)(lg2)^2+(1/2)lg2*lg5+(1/2)(2-lg2)
=(1/2)*[(lg2)^2+lg2*lg5-lg2+2]
=(1/2)
=(1/2)*2
=1 原帖由 Kitten 于 2008-10-17 03:47 发表 http://bbs.aptx.cn/images/common/back.gif
=(1/2)(lg2)^2+(1/2)lg2*lg5+(1/2)(2-lg2)
=(1/2)*[(lg2)^2+lg2*lg5-lg2+2]
=(1/2)
=(1/2)*2
=1
Good job
[ 本帖最后由 hiddern70 于 2008-10-17 12:33 编辑 ] 谢谢二位啦~~ 我全部还给老师了m1 (54)k m1 (54)k 很好很强大的两位~! 原帖由 Kitten 于 2008-10-17 03:47 发表 http://bbs.aptx.cn/images/common/back.gif
=(1/2)(lg2)^2+(1/2)lg2*lg5+(1/2)(2-lg2)
=(1/2)*[(lg2)^2+lg2*lg5-lg2+2]
=(1/2)
=(1/2)*2
=1
GJ~
数学果然太久没动就不行了...
lg√x=lgx^(1/2)都没想到- - 我对数学完全不感兴趣的说m1 (22)k
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